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4x4x4 Disparity Algorithms

When the last two pairs are not matched.

When you still have to solve the last two edge elements you do not have a third set to reset the centres with.

The last pair to be solved are placed on ether side of the front face.  For the edges to be paired correctly they should be on the same layer with the same colour on the front face.  If they are not use either of the first two algorithms on this page.

 

(Dd) R F' U R' F (Dd)'
Down both
Clockwise
Right face
Clockwise
Front face
Anti-clock
Up face
Clockwise
Right face
Anti-clock
Front face
Clockwise
Down both
Anti-clock

Ensure the front face colours match. If not, Right clock, Top anti, Back clock.


Cross only has 3 of the 4 bars

The edges you want to flip should be on the top of the front face.

r2 U2 r2 U2 r U2 r U2
Right inn
Clockwise
Right inn
Clockwise
Up face
Clockwise
Up face
Clockwise
Right inn
Clockwise
Right inn
Clockwise
Up face
Clockwise
Up face
Clockwise
Right inn
Clockwise
Up face
Clockwise
Up face
Clockwise
Right inn
Clockwise
Up face
Clockwise
Up face
Clockwise
r' U2 B2 U' r' U B2 U' r U'  
 
Right inn
Anti-clock
Up face
Clockwise
Up face
Clockwise
Back face
Anti-clock
Back face
Anti-clock
Up face
Anti-clock
Right inn
Anti-clock
Up face
Clockwise
Back face
Anti-clock
Back face
Anti-clock
Up face
Anti-clock
Right inn
Clockwise
Up face
Anti-clock
 

Solved but for the opposite or adjacent edges in the wrong position.

This algorithm solves the cube for Fig.1 and resets the layer to a 3x3x3 solvable configuration for Fig2.  In each case an incorrectly positioned pair of edges must be at the top of the front face with a correctly positioned pair at the top of right face.

Fig.1

Fig.2
r2 U2  r2 (Uu)2 r2 (Uu)2 U2
Right inn
Clockwise
Right inn
Clockwise
Up face
Clockwise
Up face
Clockwise
Right inn
Clockwise
Right inn
Clockwise
Up both
Clockwise
Up bath
Clockwise
Right inn
Clockwise
Right inn
Clockwise
Up both
Clockwise
Up both
Clockwise
Up face
Clockwise
Up face
Clockwise

 

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